Real-Life Math -- Solution
The Thompsons' pool needs a super chlorinating. This is how you
figure out the volume of the round pool:
Area = 6.5
ft x 6.5 ft x 3.14
Area = 132.66 square feet
Volume =
132.66 square feet x 5 ft
Volume = 663.3 cubic feet
You
also need to know that 1 gallon equals 231 cubic inches and 1 cubic foot equals
1,728 cubic inches.
Total volume = 663.3 cubic feet x
1,728 cubic inches per cubic foot
Total volume = 1,146,182 cubic inches
Total
volume of the pool in cubic inches is 1,146,182.
Now, convert to gallons:
Gallons
= 1,146,182 cubic inches / 231 cubic inches per gallon
Gallons = 4,962
There
are 4,962 gallons in their pool.
Now you want to super chlorinate.
This is how much chlorine you will put in the pool:
Super chlorinate:
1
gallon liquid chlorine per 10,000 gallons pool water
4,962 gallons pool
water / 10,000 gallons pool water per gallon of liquid chlorine = 0.4962 gallons
of chlorine
You will need to add 0.4962 gallons
of chlorine to the pool. Now the family can enjoy the water.