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Pool and Spa Operator

Real-Life Activities

Real-Life Math -- Solution

The Thompsons' pool needs a super chlorinating. This is how you figure out the volume of the round pool:

Area = 6.5 ft x 6.5 ft x 3.14
Area = 132.66 square feet

Volume = 132.66 square feet x 5 ft
Volume = 663.3 cubic feet

You also need to know that 1 gallon equals 231 cubic inches and 1 cubic foot equals 1,728 cubic inches.

Total volume = 663.3 cubic feet x 1,728 cubic inches per cubic foot
Total volume = 1,146,182 cubic inches

Total volume of the pool in cubic inches is 1,146,182.

Now, convert to gallons:

Gallons = 1,146,182 cubic inches / 231 cubic inches per gallon
Gallons = 4,962

There are 4,962 gallons in their pool.

Now you want to super chlorinate. This is how much chlorine you will put in the pool:

Super chlorinate:

1 gallon liquid chlorine per 10,000 gallons pool water
4,962 gallons pool water / 10,000 gallons pool water per gallon of liquid chlorine = 0.4962 gallons of chlorine

You will need to add 0.4962 gallons of chlorine to the pool. Now the family can enjoy the water.


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